我错过了一种以透明方式将数据添加到 SO 答案的方法。我的经验是，来自 dput() 的 structure 对象有时会使没有经验的用户感到不必要的困惑。但是，我没有耐心每次都将其复制/粘贴到一个简单的数据框中，并希望将其自动化。类似于 dput() 的东西，但在简化版本中。
说我通过复制/粘贴和其他一些房东有这样的数据，
Df <- data.frame(A = c(2, 2, 2, 6, 7, 8),
B = c("A", "G", "N", NA, "L", "L"),
C = c(1L, 3L, 5L, NA, NA, NA))
看起来像这样，
Df
#> A B C
#> 1 2 A 1
#> 2 2 G 3
#> 3 2 N 5
#> 4 6 <NA> NA
#> 5 7 L NA
#> 6 8 L NA
在一个整数、一个因子和一个数值向量内，
str(Df)
#> 'data.frame': 6 obs. of 3 variables:
#> $ A: num 2 2 2 6 7 8
#> $ B: Factor w/ 4 levels "A","G","L","N": 1 2 4 NA 3 3
#> $ C: int 1 3 5 NA NA NA
现在，我想在 SO 上分享这个，但我并不总是拥有它来自的 原始 数据框。我通常以 SO 形式 pipe() 它，而我知道的唯一方法是 dput()。喜欢，
dput(Df)
#> structure(list(A = c(2, 2, 2, 6, 7, 8), B = structure(c(1L, 2L,
#> 4L, NA, 3L, 3L), .Label = c("A", "G", "L", "N"), class = "factor"),
#> C = c(1L, 3L, 5L, NA, NA, NA)), .Names = c("A", "B", "C"), row.names = c(NA,
#> -6L), class = "data.frame")
但是，正如我在顶部所说，这些 structure 看起来很困惑。出于这个原因，我正在寻找一种以某种方式压缩 dput() 输出的方法。我想像这样的输出，
dput_small(Df)
#> data.frame(A = c(2, 2, 2, 6, 7, 8), B = c("A", "G", "N", NA, "L", "L"),
#> C = c(1L, 3L, 5L, NA, NA, NA))
这可能吗？我意识到还有其他类，例如 lists、tbl、tbl_df 等。
最佳答案
编辑:将较旧的解决方案留在底部，因为它获得了赏金和许多选票，但提出了改进的答案
您可以使用 {constructive} package ，现在仅在 GitHub 上，但在您阅读本文时可能在 CRAN 上:
# remotes::install_github("cynkra/constructive")
Df <- data.frame(A = c(2, 2, 2, 6, 7, 8),
B = c("A", "G", "N", NA, "L", "L"),
C = c(1L, 3L, 5L, NA, NA, NA))
constructive::construct(Df)
#> data.frame(
#> A = c(2, 2, 2, 6, 7, 8),
#> B = c("A", "G", "N", NA, "L", "L"),
#> C = c(1L, 3L, 5L, NA, NA, NA)
#> )
它具有许多通用类的自定义构造函数，因此它应该能够以人类可读的方式忠实地再现大多数对象。
旧解决方案:
3 solutions :
a wrapper around
dput(handles standarddata.frames,tibblesandlists)a
read.tablesolution (fordata.frames)a
tibble::tribblesolution (fordata.frames, returning atibble)All include
nandrandomparameter which allow one to dput only the head of the data or sample it on the fly.
dput_small1(Df)
# Df <- data.frame(
# A = c(2, 2, 2, 6, 7, 8),
# B = structure(c(1L, 2L, 4L, NA, 3L, 3L), .Label = c("A", "G", "L",
# "N"), class = "factor"),
# C = c(1L, 3L, 5L, NA, NA, NA) ,
# stringsAsFactors=FALSE)
dput_small2(Df,stringsAsFactors=TRUE)
# Df <- read.table(sep="\t", text="
# A B C
# 2 A 1
# 2 G 3
# 2 N 5
# 6 NA NA
# 7 L NA
# 8 L NA", header=TRUE, stringsAsFactors=TRUE)
dput_small3(Df)
# Df <- tibble::tribble(
# ~A, ~B, ~C,
# 2, "A", 1L,
# 2, "G", 3L,
# 2, "N", 5L,
# 6, NA_character_, NA_integer_,
# 7, "L", NA_integer_,
# 8, "L", NA_integer_
# )
# Df$B <- factor(Df$B)
dput此选项提供的输出非常接近问题中提出的输出。它非常通用，因为它实际上包裹在 dput 周围，但单独应用于列。
multiline 表示'keep dput's default output layout into multiple lines'。
dput_small1<- function(x,
name=as.character(substitute(x)),
multiline = TRUE,
n=if ('list' %in% class(x)) length(x) else nrow(x),
random=FALSE,
seed = 1){
name
if('tbl_df' %in% class(x)) create_fun <- "tibble::tibble" else
if('list' %in% class(x)) create_fun <- "list" else
if('data.table' %in% class(x)) create_fun <- "data.table::data.table" else
create_fun <- "data.frame"
if(random) {
set.seed(seed)
if(create_fun == "list") x <- x[sample(1:length(x),n)] else
x <- x[sample(1:nrow(x),n),]
} else {
x <- head(x,n)
}
line_sep <- if (multiline) "\n " else ""
cat(sep='',name," <- ",create_fun,"(\n ",
paste0(unlist(
Map(function(item,nm) paste0(nm,if(nm=="") "" else " = ",paste(capture.output(dput(item)),collapse=line_sep)),
x,if(is.null(names(x))) rep("",length(x)) else names(x))),
collapse=",\n "),
if(create_fun == "data.frame") ",\n stringsAsFactors = FALSE)" else "\n)")
}
dput_small1(list(1,2,c=3,d=4),"my_list",random=TRUE,n=3)
# my_list <- list(
# 2,
# d = 4,
# c = 3
# )
read.table解决方案对于 data.frames，我觉得以更明确/表格格式的输入很舒服。
这可以使用 read.table 来实现，然后自动重新格式化 read.table 无法正确设置的列类型。不像第一个解决方案那样通用，但在 SO 上发现的 95% 的情况下都能顺利工作。
dput_small2 <- function(df,
name=as.character(substitute(df)),
sep='\t',
header=TRUE,
stringsAsFactors = FALSE,
n= nrow(df),
random=FALSE,
seed = 1){
name
if(random) {
set.seed(seed)
df <- df[sample(1:nrow(df),n),]
} else {
df <- head(df,n)
}
cat(sep='',name,' <- read.table(sep="',sub('\t','\\\\t',sep),'", text="\n ',
paste(colnames(df),collapse=sep))
df <- head(df,n)
apply(df,1,function(x) cat(sep='','\n ',paste(x,collapse=sep)))
cat(sep='','", header=',header,', stringsAsFactors=',stringsAsFactors,')')
sapply(names(df), function(x){
if(is.character(df[[x]]) & suppressWarnings(identical(as.character(as.numeric(df[[x]])),df[[x]]))){ # if it's a character column containing numbers
cat(sep='','\n',name,'$',x,' <- as.character(', name,'$',x,')')
} else if(is.factor(df[[x]]) & !stringsAsFactors) { # if it's a factor and conversion is not automated
cat(sep='','\n',name,'$',x,' <- factor(', name,'$',x,')')
} else if(inherits(df[[x]], "POSIXct")){
cat(sep='','\n',name,'$',x,' <- as.POSIXct(', name,'$',x,')')
} else if(inherits(df[[x]], "Date")){
cat(sep='','\n',name,'$',x,' <- as.Date(', name,'$',x,')')
}})
invisible(NULL)
}
最简单的情况
dput_small2(iris,n=6)
将打印:
iris <- read.table(sep="\t", text="
Sepal.Length Sepal.Width Petal.Length Petal.Width Species
5.1 3.5 1.4 0.2 setosa
4.9 3.0 1.4 0.2 setosa
4.7 3.2 1.3 0.2 setosa
4.6 3.1 1.5 0.2 setosa
5.0 3.6 1.4 0.2 setosa
5.4 3.9 1.7 0.4 setosa", header=TRUE, stringsAsFactors=FALSE)
执行时又会返回:
# Sepal.Length Sepal.Width Petal.Length Petal.Width Species
# 1 5.1 3.5 1.4 0.2 setosa
# 2 4.9 3.0 1.4 0.2 setosa
# 3 4.7 3.2 1.3 0.2 setosa
# 4 4.6 3.1 1.5 0.2 setosa
# 5 5.0 3.6 1.4 0.2 setosa
# 6 5.4 3.9 1.7 0.4 setosa
str(iris)
# 'data.frame': 6 obs. of 5 variables:
# $ Sepal.Length: num 5.1 4.9 4.7 4.6 5 5.4
# $ Sepal.Width : num 3.5 3 3.2 3.1 3.6 3.9
# $ Petal.Length: num 1.4 1.4 1.3 1.5 1.4 1.7
# $ Petal.Width : num 0.2 0.2 0.2 0.2 0.2 0.4
# $ Species : chr " setosa" " setosa" " setosa" " setosa" ...
更复杂
虚拟数据:
test <- data.frame(a=1:5,
b=as.character(6:10),
c=letters[1:5],
d=factor(letters[6:10]),
e=Sys.time()+(1:5),
stringsAsFactors = FALSE)
这个:
dput_small2(test,'df2')
将打印:
df2 <- read.table(sep="\t", text="
a b c d e
1 6 a f 2018-02-15 11:53:17
2 7 b g 2018-02-15 11:53:18
3 8 c h 2018-02-15 11:53:19
4 9 d i 2018-02-15 11:53:20
5 10 e j 2018-02-15 11:53:21", header=TRUE, stringsAsFactors=FALSE)
df2$b <- as.character(df2$b)
df2$d <- factor(df2$d)
df2$e <- as.POSIXct(df2$e)
执行时又会返回:
# a b c d e
# 1 1 6 a f 2018-02-15 11:53:17
# 2 2 7 b g 2018-02-15 11:53:18
# 3 3 8 c h 2018-02-15 11:53:19
# 4 4 9 d i 2018-02-15 11:53:20
# 5 5 10 e j 2018-02-15 11:53:21
str(df2)
# 'data.frame': 5 obs. of 5 variables:
# $ a: int 1 2 3 4 5
# $ b: chr "6" "7" "8" "9" ...
# $ c: chr "a" "b" "c" "d" ...
# $ d: Factor w/ 5 levels "f","g","h","i",..: 1 2 3 4 5
# $ e: POSIXct, format: "2018-02-15 11:53:17" "2018-02-15 11:53:18" "2018-02-15 11:53:19" "2018-02-15 11:53:20" ...
all.equal(df2,test)
# [1] "Component “e”: Mean absolute difference: 0.4574251" # only some rounding error
tribble解决方案read.table 选项可读性很强，但不是很通用。 tribble 几乎可以处理任何数据类型(尽管因素需要临时修复)。
此解决方案对于 OP 的示例不是很有用，但对于列表列非常有用(请参见下面的示例)。要使用输出，需要库 tibble。
就像我的第一个解决方案一样，它是 dput 的包装器，但不是“dputting”列，而是“dputting”元素。
dput_small3 <- function(df,
name=as.character(substitute(df)),
n= nrow(df),
random=FALSE,
seed = 1){
name
if(random) {
set.seed(seed)
df <- df[sample(1:nrow(df),n),]
} else {
df <- head(df,n)
}
df1 <- lapply(df,function(col) if(is.factor(col)) as.character(col) else col)
dputs <- sapply(df1,function(col){
col_dputs <- sapply(col,function(elt) paste(capture.output(dput(elt)),collapse=""))
max_char <- max(nchar(unlist(col_dputs)))
sapply(col_dputs,function(elt) paste(c(rep(" ",max_char-nchar(elt)),elt),collapse=""))
})
lines <- paste(apply(dputs,1,paste,collapse=", "),collapse=",\n ")
output <- paste0(name," <- tibble::tribble(\n ",
paste0("~",names(df),collapse=", "),
",\n ",lines,"\n)")
cat(output)
sapply(names(df), function(x) if(is.factor(df[[x]])) cat(sep='','\n',name,'$',x,' <- factor(', name,'$',x,')'))
invisible(NULL)
}
dput_small3(dplyr::starwars[c(1:3,11)],"sw",n=6,random=TRUE)
# sw <- tibble::tribble(
# ~name, ~height, ~mass, ~films,
# "Lando Calrissian", 177L, 79, c("Return of the Jedi", "The Empire Strikes Back"),
# "Finis Valorum", 170L, NA_real_, "The Phantom Menace",
# "Ki-Adi-Mundi", 198L, 82, c("Attack of the Clones", "The Phantom Menace", "Revenge of the Sith"),
# "Grievous", 216L, 159, "Revenge of the Sith",
# "Wedge Antilles", 170L, 77, c("Return of the Jedi", "The Empire Strikes Back", "A New Hope"),
# "Wat Tambor", 193L, 48, "Attack of the Clones"
# )
https://stackoverflow.com/questions/18746456/