我有一个 Controller ,其 POST 处理程序定义如下:
@RequestMapping(value="/ajax/saveVendor.do", method = RequestMethod.POST)
public @ResponseBody AjaxResponse saveVendor( @Valid UIVendor vendor,
BindingResult result,
Locale currentLocale )
当以 JSON 格式查看时,UIVendor 对象如下所示:
var vendor =
{
vendorId: 123,
vendorName: "ABC Company",
emails : [
{ emailAddress: "abc123@abc.com", flags: 2 },
{ emailAddress: "xyz@abc.com", flags: 3 }
]
}
UIVendor bean 有一个名为“Emails”的 ArrayList 类型的字段,带有适当的 setter 和 getter (getEmails/setEmails)。 NotificationEmail 对象也有适当的公共(public) setter/getter。
当我尝试使用以下代码发布对象时:
$.post("ajax/saveVendor.do", $.param(vendor), saveEntityCallback, "json" );
我在日志中收到此错误:
Invalid property 'emails[0][emailAddress]' of bean class [beans.UIVendor]: Property referenced in indexed property path 'emails[0][emailAddress]' is neither an array nor a List nor a Map; returned value was [abc123@abc.com]
我如何正确地将这样的嵌套对象发布到 Spring Controller 并使其正确反序列化为适当的对象结构。
更新 根据 Bohzo 的要求,这里是 UIVendor 类的内容。这个类包装了一个 web 服务生成的 bean 类,将 VendorAttributes 暴露为单独的字段:
package com.mycompany.beans;
import java.util.*;
import org.apache.commons.lang.*;
import com.mycompany.domain.Vendor;
import com.mycompany.domain.VendorAttributes;
import org.apache.commons.logging.*;
import org.codehaus.jackson.annotate.JsonIgnore;
public class UIVendor
{
private final Log logger = LogFactory.getLog( this.getClass() );
private Vendor vendor;
private boolean ftpFlag;
private String ftpHost;
private String ftpPath;
private String ftpUser;
private String ftpPassword;
private List<UINotificationEmail> emails = null;
public UIVendor() { this( new Vendor() ); }
public UIVendor( Vendor vendor )
{
this.vendor = vendor;
loadVendorAttributes();
}
private void loadVendorAttributes()
{
this.ftpFlag = false;
this.ftpHost = this.ftpPassword = this.ftpPath = this.ftpUser = "";
this.emails = null;
for ( VendorAttributes a : this.vendor.getVendorAttributes() )
{
String key = a.getVendorFakey();
String value = a.getVendorFaValue();
int flags = a.getFlags();
if ( StringUtils.isBlank(key) || StringUtils.isBlank(value) ) continue;
if ( key.equals( "ftpFlag" ) )
{
this.ftpFlag = BooleanUtils.toBoolean( value );
}
else if ( key.equals( "ftpHost" ) )
{
this.ftpHost = value;
}
else if ( key.equals("ftpPath") )
{
this.ftpPath = value;
}
else if ( key.equals("ftpUser") )
{
this.ftpUser = value;
}
else if ( key.equals("ftpPassword") )
{
this.ftpPassword = value;
}
else if ( key.equals("email") )
{
UINotificationEmail email = new UINotificationEmail(value, flags);
this.getEmails().add( email );
}
}
}
private void saveVendorAttributes()
{
int id = this.vendor.getVendorId();
List<VendorAttributes> attrs = this.vendor.getVendorAttributes();
attrs.clear();
if ( this.ftpFlag )
{
VendorAttributes flag = new VendorAttributes();
flag.setVendorId( id );
flag.setStatus( "A" );
flag.setVendorFakey( "ftpFlag" );
flag.setVendorFaValue( BooleanUtils.toStringTrueFalse( this.ftpFlag ) );
attrs.add( flag );
if ( StringUtils.isNotBlank( this.ftpHost ) )
{
VendorAttributes host = new VendorAttributes();
host.setVendorId( id );
host.setStatus( "A" );
host.setVendorFakey( "ftpHost" );
host.setVendorFaValue( this.ftpHost );
attrs.add( host );
if ( StringUtils.isNotBlank( this.ftpPath ) )
{
VendorAttributes path = new VendorAttributes();
path.setVendorId( id );
path.setStatus( "A" );
path.setVendorFakey( "ftpPath" );
path.setVendorFaValue( this.ftpPath );
attrs.add( path );
}
if ( StringUtils.isNotBlank( this.ftpUser ) )
{
VendorAttributes user = new VendorAttributes();
user.setVendorId( id );
user.setStatus( "A" );
user.setVendorFakey( "ftpUser" );
user.setVendorFaValue( this.ftpUser );
attrs.add( user );
}
if ( StringUtils.isNotBlank( this.ftpPassword ) )
{
VendorAttributes password = new VendorAttributes();
password.setVendorId( id );
password.setStatus( "A" );
password.setVendorFakey( "ftpPassword" );
password.setVendorFaValue( this.ftpPassword );
attrs.add( password );
}
}
}
for ( UINotificationEmail e : this.getEmails() )
{
logger.debug("Adding email " + e );
VendorAttributes email = new VendorAttributes();
email.setStatus( "A" );
email.setVendorFakey( "email" );
email.setVendorFaValue( e.getEmailAddress() );
email.setFlags( e.getFlags() );
email.setVendorId( id );
attrs.add( email );
}
}
@JsonIgnore
public Vendor getVendor()
{
saveVendorAttributes();
return this.vendor;
}
public int getVendorId()
{
return this.vendor.getVendorId();
}
public void setVendorId( int vendorId )
{
this.vendor.setVendorId( vendorId );
}
public String getVendorType()
{
return this.vendor.getVendorType();
}
public void setVendorType( String vendorType )
{
this.vendor.setVendorType( vendorType );
}
public String getVendorName()
{
return this.vendor.getVendorName();
}
public void setVendorName( String vendorName )
{
this.vendor.setVendorName( vendorName );
}
public String getStatus()
{
return this.vendor.getStatus();
}
public void setStatus( String status )
{
this.vendor.setStatus( status );
}
public boolean isFtpFlag()
{
return this.ftpFlag;
}
public void setFtpFlag( boolean ftpFlag )
{
this.ftpFlag = ftpFlag;
}
public String getFtpHost()
{
return this.ftpHost;
}
public void setFtpHost( String ftpHost )
{
this.ftpHost = ftpHost;
}
public String getFtpPath()
{
return this.ftpPath;
}
public void setFtpPath( String ftpPath )
{
this.ftpPath = ftpPath;
}
public String getFtpUser()
{
return this.ftpUser;
}
public void setFtpUser( String ftpUser )
{
this.ftpUser = ftpUser;
}
public String getFtpPassword()
{
return this.ftpPassword;
}
public void setFtpPassword( String ftpPassword )
{
this.ftpPassword = ftpPassword;
}
public List<UINotificationEmail> getEmails()
{
if ( this.emails == null )
{
this.emails = new ArrayList<UINotificationEmail>();
}
return emails;
}
public void setEmails(List<UINotificationEmail> emails)
{
this.emails = emails;
}
}
更新 2 这是 Jackson 的输出:
{
"vendorName":"MAIL",
"vendorId":45,
"emails":
[
{
"emailAddress":"dfg",
"success":false,
"failure":false,
"flags":0
}
],
"vendorType":"DFG",
"ftpFlag":true,
"ftpHost":"kdsfjng",
"ftpPath":"dsfg",
"ftpUser":"sdfg",
"ftpPassword":"sdfg",
"status":"A"
}
这是我在 POST 中返回的对象的结构:
{
"vendorId":"45",
"vendorName":"MAIL",
"vendorType":"DFG",
"ftpFlag":true,
"ftpHost":"kdsfjng",
"ftpUser":"sdfg",
"ftpPath":"dsfg",
"ftpPassword":"sdfg",
"status":"A",
"emails":
[
{
"success":"false",
"failure":"false",
"emailAddress":"dfg"
},
{
"success":"true",
"failure":"true",
"emailAddress":"pfc@sj.org"
}
]
}
我也尝试过使用来自 www.json.org 的 JSON 库进行序列化,结果正是您在上面看到的。但是,当我发布该数据时,传递给 Controller 的 UIVendor 对象中的所有字段都是空的(尽管对象不是)。
最佳答案
更新:自 Spring 3.1 起,可以使用 @Valid On @RequestBody Controller Method Arguments .
@RequestMapping(value="/ajax/saveVendor.do", method = RequestMethod.POST)
public @ResponseBody AjaxResponse saveVendor( @Valid @RequestBody UIVendor vendor,
BindingResult result,
Locale currentLocale )
经过多次反复试验,我终于尽可能地弄清楚了问题所在。使用以下 Controller 方法签名时:
@RequestMapping(value="/ajax/saveVendor.do", method = RequestMethod.POST)
public @ResponseBody AjaxResponse saveVendor( @Valid UIVendor vendor,
BindingResult result,
Locale currentLocale )
客户端脚本必须以 post-data(通常为“application/x-www-form-urlencoded”)格式(即 field=value&field2=value2)传递对象中的字段。这是在 jQuery 中完成的,如下所示:
$.post( "mycontroller.do", $.param(object), callback, "json" )
这适用于没有子对象或集合的简单 POJO 对象,但是一旦您对传递的对象引入了显着的复杂性,Spring 的映射逻辑就无法识别 jQuery 用于序列化对象数据的表示法:
object[0][field]
我解决这个问题的方法是将 Controller 中的方法签名更改为:
@RequestMapping(value="/ajax/saveVendor.do", method = RequestMethod.POST)
public @ResponseBody AjaxResponse saveVendor( @RequestBody UIVendor vendor,
Locale currentLocale )
并将来自客户端的调用更改为:
$.ajax(
{
url:"ajax/mycontroller.do",
type: "POST",
data: JSON.stringify( objecdt ),
success: callback,
dataType: "json",
contentType: "application/json"
} );
这需要使用 JSON javascript库。它还强制 contentType 为“application/json”,这是 Spring 在使用 @RequestBody 注解时所期望的,并将对象序列化为 Jackson 可以反序列化为有效对象结构的格式。
唯一的副作用是现在我必须在 Controller 方法中处理我自己的对象验证,但这相对简单:
BindingResult result = new BeanPropertyBindingResult( object, "MyObject" );
Validator validator = new MyObjectValidator();
validator.validate( object, result );
如果有人对改进此过程有任何建议,我会全力以赴。
关于jquery - 使用 JSON 将嵌套对象发布到 Spring MVC Controller ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5900840/
相关文章:
java - 使用 JSONObject 在 Java 中为以下结构创建嵌套 JSON 对象?
ajax - django:使用 json 对象测试基于 POST 的 View
java - 如何使用 Jackson 注释从 HttpResponse 反序列化 JSON 对象?
jquery - 来源http ://localhost is not allowed by Acc
c# - 发布到 Web API 时出现不支持的媒体类型错误
javascript - 将 JSON 数据从 php 传递给 html-data 属性,然后传递给