我有一个 json 数组，看起来像这样:

  {
    "id": 1,
    "children": [
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    },
    {
        "id": 2,
        "children": {
            "id": 3,
            "children": {
                "id": 4,
                "children": ""
            }
        }
    }]
}

我想要一个函数来删除“ child ”为空的元素。我该怎么做？我不求答案，只求建议

最佳答案

要遍历对象的键，请使用 for .. in 循环:

for (var key in json_obj) {
    if (json_obj.hasOwnProperty(key)) {
        // do something with `key'
    }
}

要测试所有元素的空子元素，您可以使用递归方法:遍历所有元素并递归测试它们的子元素。

可以使用 delete 关键字来删除对象的属性:

var someObj = {
    "one": 123,
    "two": 345
};
var key = "one";
delete someObj[key];
console.log(someObj); // prints { "two": 345 }

文档:

• https://developer.mozilla.org/en-US/docs/JavaScript/Guide/Working_with_Objects
• https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Statements/for...in
• https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Operators/delete

https://stackoverflow.com/questions/15451290/