问题:

我们必须创建一个游戏，让用户输入他们想要使用的铅笔数量。 通过创建一个循环来扩展您的程序。每个玩家轮流取出铅笔，直到 table 上剩下 0 支铅笔。每次迭代打印 2 行:带铅笔的行(垂直条)，现在轮到打印 NameX 的轮次子字符串。

How many pencils would you like to use:
> 5
Who will be the first (John, Jack):
> John
|||||
John's turn:
> 2
|||
Jack's turn:
> 1
||
John's turn:
> 2

我的解决方案:

person = input("Who will be the first (John, Jack):")
print("|" * number_of_pencil)
print(f"{person}'s turn")

while number_of_pencil > 1:
    pencil = int(input())
    number_of_pencil -= pencil
    print("|" * number_of_pencil)
    if person == "John":
        print("Jack's turn")
        person = "Jack"
    else:
        print("John's turn")
        person = "John"

输出:

Who will be the first (John, Jack):> John
|||||
John's turn
> 2
|||
Jack's turn
> 1
||
John's turn
> 2

Jack's turn

需要的建议:我应该如何打破循环？

最佳答案

下面的代码应该可以工作:

number_of_pencil = int(input("How many pencils would you like to use: "))
person = input("Who will be the first (John, Jack): ")
print("|" * number_of_pencil)

while number_of_pencil > 1:
    if person == "John":
        print("John's turn")
        person = "Jack"
    else:
        print("Jack's turn")
        person = "John"
    pencil = int(input())
    number_of_pencil -= pencil
    if number_of_pencil > 0:
      print("|" * number_of_pencil)

示例:

How many pencils would you like to use: 5
Who will be the first (John, Jack): John
|||||
John's turn
2
|||
Jack's turn
1
||
John's turn
2

我们可以将它们移到开头，这样它们只会在有剩余铅笔时才运行，而不是让打印语句在循环结束时指示是否轮到 John 或 Jack。

此外，如果还有铅笔，我们只会打印剩余铅笔的数量。

希望对您有所帮助!如果您有任何问题，请告诉我!

https://stackoverflow.com/questions/72919715/